Center mass of triangle in 3-D space

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SUMMARY

The discussion focuses on finding the centroid of a triangle in 3-D space defined by vertices A (4,2,0), B (3,3,0), and C (1,1,3). The centroid can be calculated using the formula for the mean of the coordinates of the vertices: \(\left(\frac{x_1+ x_2+ x_3}{3}, \frac{y_1+y_2+y_3}{3}, \frac{z_1+z_2+z_3}{3}\right)\). The medians of the triangle intersect at a point that divides each median in a 2:1 ratio, allowing for a simplified calculation by selecting any median. This method confirms that the centroid serves as the intersection point of the medians.

PREREQUISITES
  • Understanding of 3-D coordinate geometry
  • Knowledge of centroid and median concepts in triangles
  • Familiarity with the properties of geometric figures
  • Ability to perform basic arithmetic operations with coordinates
NEXT STEPS
  • Study the properties of centroids in various geometric shapes
  • Learn about the derivation and applications of the median theorem in triangles
  • Explore the implications of centroid calculations in physics and engineering
  • Investigate the differences between centroid and center of mass in various contexts
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Mathematicians, geometry students, educators, and professionals in fields requiring spatial analysis or geometric computations.

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Homework Statement


So I have a triangle with points: A (4,2,0), B (3,3,0), and C (1,1,3). We are to find the point at which the three medians intersect in i,j,k format. I've found the midpoints of each side but I don't know where to go from there.
 
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Construct the equation of the line joining the midpoint and the opposite vertex. Do this for all vertices.
 
You can save a good bit of this work if you are allowed to use the theorem which states that the medians of a triangle intersect at a point with divides each median in the ratio of 2:1 . Then you can choose any one median and find the point (by proportions) which is one-third of the way from the base to the opposite vertex. (Any other choice of a median to work with should give exactly the same result.)

I am presuming in this that the problem is not asking you to show that all three medians meet at the point with this property.
 
The simplest way to do this: the coordinates of the centroid of a triangle (not, strictly speaking, the "center of mass" because a geometric figure does not have 'mass') is the mean of the coordinates of the three vertices. That is, if the vertices of the triangle are at (x_1, y_1, z_1), (x_2, y_2, z_2), (x_3, y_3, z_3), then the centroid is at <br /> \left(\frac{x_1+ x_2+ x_3}{3}, \frac{y_1+y_2+y_3}{3}, \frac{z_1+z_2+z_3}{3}\right)<br /> <br /> If you don't have that theorem, use that as a check.<br /> (The average of the coordinates works for the two dimensional triangle or three dimensional tetrahedron but not for other figures.)
 

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