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Center of Gravity of a Triangle Proof

  1. Sep 16, 2009 #1
    1. The problem statement, all variables and given/known data

    The "center of gravity" of the triangle with vertices at A, B, and C is the point 1/3(A+B+C). Show that the center of gravity of a triangle is always the same as that of the triangle formed by the midpoints of its sides.


    2. Relevant equations



    3. The attempt at a solution

    I have no idea where to even begin. =/ I drew the triangle formed by the midpoints of the sides and called it DEF....
     
  2. jcsd
  3. Sep 16, 2009 #2

    Dick

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    The midpoint D of the side AB is D=(A+B)/2. Etc.
     
  4. Sep 16, 2009 #3
    Thanks for the hint!
     
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