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Main Question or Discussion Point
I am building a stand for my LCD/LED TV and Mount. See several pics below: Calculation Sheet, Mount Diagrams, and Side View of the TV. The Mount will be hanging on 2 poles, and the TV hangs on the front of the Mount.
Am I computing the Center of Gravity correctly? in order to determine where to let the whole connected device hang, so it will be centered on my stand, distributing the weight at the center?
I show my Calculation Sheet in one of the attachments, but basically the final formula filled in with weights and distances is:
Center of Gravity = (4.75 in)x(36 lbs) + (10 15/16 in)x(49.8 lbs) / (36 + 49.8) lbs = 8.341 in
where
4.75 and 36 are the Center of the Mount and Mount Weight,
and
10 15/16 and 49.8 are the Center of the TV and TV Weight,
Length measurements are taken by setting the back of the Mount as 0. Then, later translating the interval to the back of the Stand.
The more I think about it, does the point of weight also have to do with the lever action of the 2 poles holding the weight up, on the stand? I also decided to let the poles rest on the ground, after passing them through my stand ... so this is really more about balancing the whole, so there is the least chance of it toppling over.
Please discuss and help me determine a best position for the 2, 2" holes for the poles.
Currently, I calculate 6.159 in. (center of poles being 3 in. from the back of the Mount) from the back edge of the 23 in. deep Stand, will place the Center of Gravity at 8.341 inches of the Mount and TV, over the center of the stand (from back to front).
Does this make sense?
Am I computing the Center of Gravity correctly? in order to determine where to let the whole connected device hang, so it will be centered on my stand, distributing the weight at the center?
I show my Calculation Sheet in one of the attachments, but basically the final formula filled in with weights and distances is:
Center of Gravity = (4.75 in)x(36 lbs) + (10 15/16 in)x(49.8 lbs) / (36 + 49.8) lbs = 8.341 in
where
4.75 and 36 are the Center of the Mount and Mount Weight,
and
10 15/16 and 49.8 are the Center of the TV and TV Weight,
Length measurements are taken by setting the back of the Mount as 0. Then, later translating the interval to the back of the Stand.
The more I think about it, does the point of weight also have to do with the lever action of the 2 poles holding the weight up, on the stand? I also decided to let the poles rest on the ground, after passing them through my stand ... so this is really more about balancing the whole, so there is the least chance of it toppling over.
Please discuss and help me determine a best position for the 2, 2" holes for the poles.
Currently, I calculate 6.159 in. (center of poles being 3 in. from the back of the Mount) from the back edge of the 23 in. deep Stand, will place the Center of Gravity at 8.341 inches of the Mount and TV, over the center of the stand (from back to front).
Does this make sense?
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