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## Homework Statement

A man of mass 84.4 Kg is in the back of a boat of mass 425 kg which is moving without friction on ice with velocity 4.16 m/s. the man moves from the back to the top of the boat with velocity 2.08 m/s traveling for 18.2m. How much distance does the boat travel while the man moves?

## Homework Equations

v[tex]_{cm}[/tex] = (v[tex]_{1}[/tex]m[tex]_{1}[/tex] + v[tex]_{2}[/tex]m[tex]_{2}[/tex])/(m[tex]_{1}[/tex]+m[tex]_{2}[/tex])

## The Attempt at a Solution

The way i try to solve this was that i put V[tex]_{cm}[/tex] = 0 because i choose a coordinate system with velocity V[tex]_{cm}[/tex]. The equation on top gives the velocity of the boat to be 0.41 m/s. Subtract this to the velocity of the boat relative to the ice gives v=3.7 m/s

Now i calculated the distance travelled: 18.2 : 2.08 = x : 3.7 which is 32.37

but it's not the same results as the book gives as a solution. What did i do wrong?