Center of Mass Problem: Finding Coordinates of a Half-Disk with Uniform Density

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SUMMARY

The discussion centers on calculating the center of mass for a half-disk with a uniform density of 3 kg and a radius of 1 meter, positioned in the xy-plane with its diameter along the y-axis. The formula provided for the x-coordinate of the center of mass is x coord = ∫(x * density(x) * Area of Slice(x) dx) / ∫(density(x) dx). Participants emphasize the importance of understanding each term in the equation before proceeding with the calculations. The discussion encourages users to share their approaches to solving this problem.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with the concept of center of mass
  • Knowledge of uniform density distributions
  • Basic geometry of circular shapes
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  • Study the derivation of the center of mass formula for different shapes
  • Learn about calculating integrals involving circular areas
  • Explore applications of center of mass in physics and engineering
  • Investigate numerical methods for solving integrals when analytical solutions are complex
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Students in physics or engineering, mathematicians interested in applied calculus, and anyone involved in mechanics or material science looking to understand the center of mass calculations for various shapes.

Hexagram1000
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The Problem is the following:
One half of a uniform circular disk of radisu 1 meter lies in the xy-plane with its diameter along the y-axis, its center at the origin, and x>0. The mass of the hallf-disk is 3 kg. Find(xcoord of center of mass, y-coord of center of mass)
The equation of the center of mass of the coord is the following:
x coord of center of mass = \intx * density(x)AreaofSlice(x)dx\div\intdensity(x)dx

or
x coord = \intmassofslice * x \div\div massofslice

How would you do this problem
 
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Hexagram1000 said:
How would you do this problem

it is more than just how we would do this problem but we wish to know how you may tackle it too.


hint: perhaps first sort out what those entries in the equation mean and then go fromt there
 

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