Center of Mass Projectile Problem

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Homework Help Overview

The problem involves a projectile of mass 19.4 kg fired at an angle of 57.0 degrees with an initial speed of 81.0 m/s. At its highest point, the projectile explodes into two equal mass fragments, with one fragment falling vertically. The discussion focuses on the calculations related to the center of mass and the positions of the fragments after the explosion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the center of mass and the positions of the fragments after the explosion, raising questions about the interpretation of vertical motion and the reference frame used for calculations.

Discussion Status

Participants are actively engaging with the calculations presented, questioning specific values and assumptions made by the original poster. There is a focus on clarifying the correct application of the center of mass concept and the implications of changing reference frames.

Contextual Notes

There are indications of confusion regarding the sign of the position of the first fragment and the total mass used in calculations. The original poster's choice to redefine the origin for the center of mass is also under scrutiny.

itsme24
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Hi, sorry stuck again!

Here is the problem:

A projectile of mass 19.4 kg is fired at an angle of 57.0 degrees above the horizontal and with a speed of 81.0 m/s. At the highest point of its trajectory the projectile explodes into two fragments with equal mass, one of which falls vertically with zero initial speed. You can ignore air resistance.

And here is what I did:

I first found the center of mass when y = 0 since the center of mass follows the trajectory of the parabola I used the equation:

y(x) = tan(theta)x - .5g(x/(V_i*cos(theta))^2

y(x) = 0
theta = 57 degrees
g= 9.8m/s^2
V_i = 81.0 m/s so...

0 = tan(57)x - 4.9(x/(8.1*cos(57))^2
0 = 1.54x - 0.00252x^2

quadratic:
x = 0, 776.1m = center of mass

Then it says that the first fragment drops vertically at the highest point and this is partly where I get confused since with my math I assumed that means straight down, correct me if I'm wrong. So I found t when V_y = 0 to find x at that point.

V_y = 0 = V_yi + a_y*t

0= 81.0*sin(57) - 9.8t
t= 6.93s

x when t = 6.93s which should give me the position fragment 1 landed:

x_f1 = x_i + V_ix*t + 0.5a_x*t^2
x_f1 = 0 + 81.0cos(57) + 0
x_f1 = 305.72m

Then I just had to find x of fragment 2:

x_cm = (m_f1*x_f1) + (m_f2*x_f2) / (m_f1 + m_f2)

so, I made the center of mass the 0 coordinate:

776.1m = [(9.7kg*-470.4m) + (9.7kg*x_f2)] / (9.7kg*2)

x_f2 = 2020m, which turned out to be wrong! :eek:

I'm sorry this problem is so long :frown:
 
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Why did x_{f1} become -470.4m, when it clearly states it's 305.27m above?

Also m_1 + m_2 is 19.4, not 9.7
 
ya sorry I had it written 9.7kg*2, I did use 19.4.

But for the x_f1 I put it to -470.4m because I put the center of mass that I found as the origin in a new axes for calculating x_f2's position.

so 776.1m became 0, which means that 776.1m-305.72m became x_f1 and since it's to the left of the new origin it would be negative. Should I not have done that?
 
If I left it at 305.27m then the math would be

776.1m = [(9.7kg*305.27m) + 9.7kg*x_f2] / 19.4kg = 1246.93 m and that answer was not correct either :(
 

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