Center of Mass: Weight Distribution for Bob & Charlie

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SUMMARY

In the discussion, Bob and Charlie, two paramedics, carry a 200 lb patient on an 8-foot stretcher. The patient's center of gravity is located 3 feet from Bob and 5 feet from Charlie. To determine the weight distribution, the torque equation must be applied, where the torques about the center of gravity must be equal in magnitude. This leads to the conclusion that Bob carries 120 lbs and Charlie carries 80 lbs of the patient's weight.

PREREQUISITES
  • Understanding of torque and its application in physics
  • Basic knowledge of weight distribution principles
  • Familiarity with center of mass calculations
  • Ability to solve linear equations
NEXT STEPS
  • Study the principles of torque in physics
  • Learn about center of mass calculations in various contexts
  • Explore weight distribution scenarios in emergency medical services
  • Review linear equation solving techniques for practical applications
USEFUL FOR

Paramedics, physics students, and professionals involved in weight distribution and load management in emergency services will benefit from this discussion.

silentshimmer
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Two paramedics, Bob and Charlie, carry a 200 lb patient on an 8-foot-long stretcher. Bob holds the front end of the stretcher and Charlie holds the back end. The patient lies closer to the front end of the stretcher, so his center of gravity is 3 feet from Bob's hands and 5 feet from Charlie's. How much of the patient's weight is carried by Bob and how much by Charlie?

where to start? what equation?
 
Physics news on Phys.org
HINT: Torque
 
The torques RXF about the cg must be equal in magnitude.
 

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