kthouz
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If F denotes the central force and is given as the inverse of the square distance
F=-k/r^2. where k>0. How can i show that F the path of the partilce under that force is a conic?
What i can see is that it is the second law of Kepler. And when i try to compare F with the former equation of conics r= (pe)/(1+ecosB). I can find p!
Just i need your help
F=-k/r^2. where k>0. How can i show that F the path of the partilce under that force is a conic?
What i can see is that it is the second law of Kepler. And when i try to compare F with the former equation of conics r= (pe)/(1+ecosB). I can find p!
Just i need your help