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Central force as a conic: How to show it?

  1. Mar 17, 2008 #1
    If F denotes the central force and is given as the inverse of the square distance
    F=-k/r^2. where k>0. How can i show that F the path of the partilce under that force is a conic?
    What i can see is that it is the second law of Kepler. And when i try to compare F with the former equation of conics r= (pe)/(1+ecosB). I can find p!
    Just i need your help
  2. jcsd
  3. Mar 28, 2008 #2

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    Here is a thread which does exactly that. You have to follow the steps patiently.
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