Centre of gravity of this system of particles

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SUMMARY

The discussion focuses on calculating the center of gravity for a system of particles with masses of 4 kg, 6 kg, and 8 kg located at specified coordinates. The correct method involves using a weighted average of the x and y components based on the masses and their positions. The calculated coordinates for the center of mass are approximately (23.33, -6.22). The negative y-coordinate indicates that the center of gravity is located below the reference point.

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pinnacleprouk
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Homework Statement



Find the centre of gravity of this system of particles

Homework Equations



attached image showing diagram

http://www.zshare.net/image/7209360586277b98/

The Attempt at a Solution



Taking moments about a, 4*0+6*30 = 184 then not sure

Any help is greatly appreciated

Thanks in advance
 
Last edited by a moderator:
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Don't worry about moments- take a "weighted" average of the components. Taking the 4 kg mass on the left to be at (0, 0), the 6 kg mass is at (30, 0) and the 8 kg mass at (30, -14). The x-coordinate of the center of mass will be at
[tex]\frac{4(0)+ 6(30)+ 8(30)}{4+ 6+ 8}[/tex]
and the y-coordinate will be
[tex]\frac{4(0)+ 6(0)+ 8(-14)}{4+ 6+ 8}[/tex]
 
Thanks for the reply, ok so I get 23.33 for x and -6.22 for y,

Providing I have calculated the sums correctly,
the minus is throwing me off in locating the centre?

Thanks again!
 

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