Centre of Mass-Energy: Griffiths Electrodynamics 4th Ed.

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Discussion Overview

The discussion revolves around the concept of the centre of mass-energy of a system of particles as presented in Griffiths Electrodynamics 4th edition. Participants explore the implications of the equations defining the centre of mass-energy and total momentum, particularly in the context of electromagnetic fields and particle interactions.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant cites Griffiths' definition of the centre of mass-energy and presents derived equations for two particles, questioning the disappearance of cross terms in position vectors.
  • Another participant suggests that the relation may only hold when including energy-momentum from electromagnetic fields, indicating a difference from classical cases.
  • A different participant claims that previous references are incorrect, asserting that the model is not realistic.
  • One participant notes that the equation does not hold when electromagnetic energy and momentum are included or when external forces are present.
  • Another participant reiterates the point about the equation's validity in the presence of electromagnetic energy and momentum or external forces.

Areas of Agreement / Disagreement

Participants express disagreement regarding the validity of the equations under certain conditions, particularly concerning electromagnetic interactions and external forces. There is no consensus on the correctness of the references cited or the applicability of the model.

Contextual Notes

The discussion highlights limitations regarding the assumptions made in the equations, particularly in relation to electromagnetic fields and external forces, which remain unresolved.

PeroK
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This is actually from Griffiths Electrodynamics 4th edition, page 546.

He defines the centre of mass-energy of a system of particles as:
$$\vec{R} = \frac{1}{E} \sum E_i \vec{r_i}$$
And gives that the total momentum of the system is:
$$\vec{P} = \frac{E}{c^2} \frac{d \vec{R}}{dt}$$
In a footnote he says that the proof of this is non-trivial and refers to a couple of papers.
I took a look at this for two particles and got:
$$\frac{d \vec{R}}{dt} = \frac{1}{(E_1 + E_2)^2}[E_1^2 \vec{u_1} + E_2^2 \vec{u_2} + E_1E_2(\vec{u_1} + \vec {u_2}) + (E_1\frac{dE_2}{dt} - E_2\frac{dE_1}{dt})(\vec{r_2} - \vec{r_1})]$$
$$= \frac{1}{(E_1 + E_2)^2}[(E_1 + E_2)(E_1 \vec{u_1} + E_2 \vec{u_2}) + (E_1\frac{dE_2}{dt} - E_2\frac{dE_1}{dt})(\vec{r_2} - \vec{r_1})]$$
$$= \frac{c^2}{E} \vec{P} + \frac{1}{E^2}[(E_1\frac{dE_2}{dt} - E_2\frac{dE_1}{dt})(\vec{r_2} - \vec{r_1})]$$
The total momentum came out but I can't see how the cross terms in the position vectors disappear. I couldn't find any specific references to this online. Any ideas about what's wrong?
 
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I might be able to answer my own question. If the particles are accelerating owing to an EM field that they themselves create, then energy and momentum are stored in the fields. This relation is only true when you include the energy-momentum from the fields. Unlike the classical case, using centre of mass, where it's generally true regardless of how the particles are accelerated.

It's clear now. Especially after reading the next page.
 
Last edited:
However the ancient references are both wrong.
Example 12.13 and Eq. (12.72) are also wrong, as is the paper in Ref. 21.
The only correct statement is "this is not a very realistic model."
 
Of course, in the case of pure neutral particle dynamics, with energy differentials zero except for collisions, the result is trivially true ...
 
The equation does not hold if electromagnetic energy and momentum are included, or if there are external forces.
 
Meir Achuz said:
The equation does not hold if electromagnetic energy and momentum are included, or if there are external forces.
Consistent with what I said ...
 

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