Centrifugal Force- Finding Speed of Satellite

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SUMMARY

The discussion centers on calculating the speed of a satellite in a stable circular orbit with a radius of 6736 km, utilizing the universal gravitational constant (6.67259 × 10−11 N·m²/kg²) and Earth's mass (5.98 × 10²⁴ kg). The key equations involved are the gravitational force equation fg=G(m1)(m2)/r² and the centripetal acceleration equation Ac=v²/r. The relationship between centripetal acceleration and radius is established, confirming that acceleration is inversely proportional to the square of the radius, leading to the conclusion that understanding this relationship is crucial for solving the problem.

PREREQUISITES
  • Understanding of gravitational force equations, specifically fg=G(m1)(m2)/r²
  • Knowledge of centripetal acceleration and its formula Ac=v²/r
  • Familiarity with the concept of circular motion in physics
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation of centripetal acceleration in circular motion
  • Explore the implications of gravitational force on satellite orbits
  • Learn about the application of Newton's law of gravitation in orbital mechanics
  • Investigate the relationship between orbital radius and satellite speed
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and orbital dynamics, as well as educators seeking to explain satellite motion and gravitational principles.

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Homework Statement



In order for a satellite to move in a stable circular orbit of radius 6736 km at a constant speed, its centripetal acceleration must be inversely proportional to the square of the radius r of the orbit.
What is the speed of the satellite? The universal gravitational constant is 6.67259 × 10−11 N · m2/kg2 and the mass if the Earth is 5.98 × 1024 kg.
Answer in units of m/s.

r=6736

Homework Equations


fg=G(m1)(m2)/r^2
Ac=v^2/r
Mv^2/r=Fg

The Attempt at a Solution



One thing that trips me up is "its centripetal acceleration must be inversely proportional to the square of the radius r of the orbit." What does this mean? Once i know this i can figure it out.
 
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That just means that in fg=G(m1)(m2)/r^2, fg = m2a so that a=Gm1/r^2. Gm1 is constant so a is proportional to 1/r^2.
 

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