Centripetal Acceleration at Equator

[physics(L)10]

Homework Statement

An individual standing at the equator:
a)What is this individuals centripetal acceleration caused by the Earth's rotation?
b)How fast would the Earth need to spin in order for the centripetal acceleration to be equal to g?

T=1 day
radius of Earth = 6.4x10^6 m

Homework Equations

a=v^2/r, v=2pir/T

The Attempt at a Solution

We need to convert the period from day to seconds and then plug in the information.

a=4pi^2r/T^2 = 4pi^2(6.4x10^6)/(1x60x60x60)

 

[ehild]

1.

The Attempt at a Solution

We need to convert the period from day to seconds and then plug in the information.

a=4pi^2r/T^2 = 4pi^2(6.4x10^6)/(1x60x60x60)

How do you convert one day to seconds?

ehild

 

[physics(L)10]

1 day x 24hrs/day x 60min/hr x 60 sec/min ... My bad, I put 60 instead of 24

 

[ehild]

Well, and do not forget to square T.

ehild

 

[physics(L)10]

So I'm right?

 

[physics(L)10]

Yeah I'm pretty sure I'm right, Thanks for your help :D :D And I figured out the last question thank you :D

 

[ehild]

You are welcome :)

ehild