Centripetal Acceleration at Equator

  • #1
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Homework Statement


An individual standing at the equator:
a)What is this individuals centripetal acceleration caused by the earths rotation?
b)How fast would the earth need to spin in order for the centripetal acceleration to be equal to g?

T=1 day
radius of earth = 6.4x10^6 m


Homework Equations


a=v^2/r, v=2pir/T


The Attempt at a Solution


We need to convert the period from day to seconds and then plug in the information.

a=4pi^2r/T^2 = 4pi^2(6.4x10^6)/(1x60x60x60)
 

Answers and Replies

  • #2
ehild
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1.

The Attempt at a Solution


We need to convert the period from day to seconds and then plug in the information.

a=4pi^2r/T^2 = 4pi^2(6.4x10^6)/(1x60x60x60)


How do you convert one day to seconds?

ehild
 
  • #3
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1 day x 24hrs/day x 60min/hr x 60 sec/min .... My bad, I put 60 instead of 24
 
  • #4
ehild
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Well, and do not forget to square T.

ehild
 
  • #6
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Yeah I'm pretty sure I'm right, Thanks for your help :D :D And I figured out the last question thank you :D
 
  • #7
ehild
Homework Helper
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You are welcome :)

ehild
 

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