Centripetal Acceleration in Terms of g?

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SUMMARY

The discussion focuses on calculating the centripetal acceleration at a radius of 8.4 cm from the center of a centrifuge spinning at 6.0x104 rpm. The formula used is Ac = v2 / r, where v is the tangential velocity derived from the given rpm. The final result should be expressed in terms of g, where g equals 9.8 m/sec2, by dividing the calculated centripetal acceleration by 9.8 m/sec2.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula
  • Knowledge of converting rpm to linear velocity
  • Familiarity with units of acceleration (m/sec2)
  • Basic grasp of gravitational acceleration (g = 9.8 m/sec2)
NEXT STEPS
  • Learn how to convert rpm to linear velocity using the formula v = 2πr * (rpm/60)
  • Study the concept of centripetal force and its relation to acceleration
  • Explore examples of expressing acceleration in terms of g for various scenarios
  • Investigate the effects of radius and speed on centripetal acceleration
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for practical examples of centripetal acceleration calculations.

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Homework Statement


Calculate the magnitude of the centripetal acceleration at 8.4 cm from the centre of the centrifuge when it is spinning at 6.0x10^4 rpm. Express your answer in terms of g (acceleration due to Earth's gravity.)


Homework Equations


Ac = v^2 /
r

The Attempt at a Solution


I know the solution i just don't understand what they are asking from me when they say:
Express your answer in terms of g (acceleration due to Earth's gravity
 
Physics news on Phys.org
g is 9.8m/sec^2. If you got an answer for the centrifuge question in m/sec^2 then just divide it by 9.8m/sec^2 to get the answer as a multiple of g.
 

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