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Centripetal Acceleration of amusement ride

  • Thread starter hsphysics2
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  • #1
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Homework Statement



An amusement ride with a radius of 4.8m allows riders to experience 4.3g's of centripetal acceleration. What is the frequency of the ride?

Homework Equations



a[itex]_{c}[/itex]= 4∏[itex]^{2}[/itex]r∫[itex]^{2}[/itex]


The Attempt at a Solution



a[itex]_{c}[/itex]=4.3
r=4.8m
∫=?


I keep getting a weird answer when I rearrange that equation to solve for ∫, and sub the values in. It might be my algebra
 

Answers and Replies

  • #2
ehild
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What acceleration does 4.3 g mean in m/s2 units?

ehild
 
  • #3
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What acceleration does 4.3 g mean in m/s2 units?

ehild
I think it's 1g=9.8m/s[itex]^{2}[/itex]
therefore 4.3g= 42.14m/s[itex]^{2}[/itex]
 
  • #4
ehild
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What do you get for the frequency?

ehild
 
  • #5
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What do you get for the frequency?

ehild
I'm getting 0.1465 for the frequency
 
  • #6
ehild
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It is not correct. How did you get it? Show your work.


ehild
 
  • #7
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It is not correct. How did you get it? Show your work.


ehild
a[itex]_{c}[/itex]=4∏[itex]^{2}[/itex]r∫[itex]^{2}[/itex]
∫[itex]^{2}[/itex]=a[itex]_{c}[/itex]/4∏[itex]^{2}[/itex]r
∫=±√(a[itex]_{c}[/itex]/4∏[itex]^{2}[/itex]r)
∫=±0.47157


*calculator mixup on the previous answer*
 
  • #8
ehild
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You need to use parentheses. ac/4∏2r means ac/4 * ∏2 * r.
The numerical value is all right, but what is the unit? And give the final result with two significant digits.

ehild
 
  • #9
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I think the unit would be hertz?

a[itex]_{c}[/itex]=4∏[itex]^{2}[/itex]r∫[itex]^{2}[/itex]
∫[itex]^{2}[/itex]=a[itex]_{c}[/itex]/(4∏[itex]^{2}[/itex]r∫[itex]^{2}[/itex])
∫=±√(a[itex]_{c}[/itex]/(4∏[itex]^{2}[/itex]r∫[itex]^{2}[/itex]))
∫=±0.47hz

So it would be 0.47hz?
 
  • #10
ehild
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fg
I think the unit would be hertz?

a[itex]_{c}[/itex]=4∏[itex]^{2}[/itex]r∫[itex]^{2}[/itex]
∫[itex]^{2}[/itex]=a[itex]_{c}[/itex]/(4∏[itex]^{2}[/itex]r∫[itex]^{2}[/itex])
∫=±√(a[itex]_{c}[/itex]/(4∏[itex]^{2}[/itex]r∫[itex]^{2}[/itex]))
∫=±0.47hz

So it would be 0.47hz?
∫[itex]^{2}[/itex]=a[itex]_{c}[/itex]/(4∏[itex]^{2}[/itex]r∫[itex]^{2}[/itex])
You kept f2 on the right hand side...[tex]f^2=\frac{a_c}{4\pi^2 r}[/tex]


Yes, it is Hz or 1/s.

ehild
 

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