# Centripetal acceleration of fairgrounds ride

1. Oct 1, 2014

### plowboy15

A fairgrounds ride spins its occupants inside a flying-saucer-shaped container. If the horizontal circular path the riders follow has a 8.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration 2.60 times that of gravity?

2. Oct 1, 2014

### TumblingDice

Welcome to PF plowboy! How far have you gotten on your end? Do you understand the physics and forces involved? Have you formulated a mathematical approach?

3. Oct 1, 2014

### plowboy15

I get you have to use ac=Vt/r and that r will equal 8 and ac= 2.60. I think you will change the formlua to ac*r=Vt

4. Oct 1, 2014

### TumblingDice

I think you're close and on the right track. Take a look at the wiki on Uniform Circular Motion here:
http://en.wikipedia.org/wiki/Circular_motion#Uniform

The equations mentioned after these texts can be simplified/adapted:
and
If we assume a mass of '1', can you see how the second equation for centripetal force simplifies￼ to the first equation for acceleration? You mentioned an acceleration 2.60 times that of gravity. Do you know how to compute 2.6g?

I hope we're both on the right track! :w

5. Oct 1, 2014

### Staff: Mentor

This thread really belongs in the homework forum, so I'm moving it there.

6. Oct 2, 2014

okay