An Earth satellite moves in a circular orbit 790 km above the Earth's surface. The period of the motion is 100.5 min.
(a) What is the speed of the satellite?
(b) What is the magnitude of the centripetal acceleration of the satellite?
a= v2 / r
T = (2 Pi r)/ V
The Attempt at a Solution
Converting km to m: 790km*(103m / 1km) = 7.90*105m
Converting min to seconds: 100.5min*(60seconds/1min) = 6.03*103seconds
Now that I have the conversions, I will solve for the unknown variables in the above formulas:
I think the radius is 7.90*105m and period is 6.03*103seconds
(a) Speed of satellite:
v=(2 pi (7.90*105m)) / (6.03*103s)
Correct answer: 7460 m/s
because the speed is incorrect, the error follows through to part (b) when substituting in speed.
How is it that it's so far off?