Centripetal acceleration question

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Homework Help Overview

The problem involves calculating the speed and centripetal acceleration of a stone being swung in a sling at different rates of rotation and lengths of the sling. The context is centered around concepts of circular motion and centripetal acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between rotation rate and centripetal acceleration, with attempts to apply relevant equations. Questions arise regarding the conversion of revolutions per second to linear speed and the correct treatment of angular velocity.

Discussion Status

Some participants have provided guidance on the equations needed to find speed and acceleration, while others express uncertainty about their understanding of the variables involved. Multiple interpretations of the equations are being explored.

Contextual Notes

There is a noted confusion regarding the treatment of angular velocity and the necessary conversions from revolutions per second. The problem does not provide explicit values for speed, leaving some participants questioning their approach.

physics_geek
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Homework Statement


Young David who slew Goliath experimented with slings before tackling the giant. He found that he could revolve a sling of length 0.800 m at the rate of 6.00 rev/s. If he increased the length to 1.100 m, he could revolve the sling only 4.00 times per second.
(a) What is the speed of the stone for each rate of rotation?
at 6.00 rev/s
at 4.00 rev/s

(b) What is the centripetal acceleration of the stone at 6.00 rev/s?


(c) What is the centripetal acceleration at 4.00 rev/s?



Homework Equations


a = v^2/r
T = 2(pi)r/v


The Attempt at a Solution


a = (6.00 rev/s)^2/.800 m = 45m/s^2





im not sure if I am even doing this rite..how do i get the speed?
do i have to convert rev/s to anythin?
 
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physics_geek said:

Homework Statement


Young David who slew Goliath experimented with slings before tackling the giant. He found that he could revolve a sling of length 0.800 m at the rate of 6.00 rev/s. If he increased the length to 1.100 m, he could revolve the sling only 4.00 times per second.
(a) What is the speed of the stone for each rate of rotation?
at 6.00 rev/s
at 4.00 rev/s

(b) What is the centripetal acceleration of the stone at 6.00 rev/s?

(c) What is the centripetal acceleration at 4.00 rev/s?

Homework Equations


a = v^2/r
T = 2(pi)r/v

The Attempt at a Solution


a = (6.00 rev/s)^2/.800 m = 45m/s^2

im not sure if I am even doing this rite..how do i get the speed?
do i have to convert rev/s to anythin?

You are on the right track but you didn't treat the 2π factor correctly.

a = v2/r

v = w * R = 2πf * R

a = (2πf* R)2/R = 4π2*f2*R
 
what do w and n stand for?
 
physics_geek said:
what do w and n stand for?

w is angular velocity little omega

And that's not N. Let me copy it in a different font.

a = v2/r

v = w * R = 2πf * R

a = (2πf * R)2/R = 4π2 * f2 * R
 
cool
thanks a lot
 

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