Why Is the Centripetal Acceleration Positive in Uniform Circular Motion?

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Homework Help Overview

The discussion revolves around a physics problem involving centripetal acceleration in the context of a child swinging a tennis ball in a horizontal circle. The original poster attempts to calculate the centripetal acceleration using given parameters, including the length of the string and the rate of revolution.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of centripetal acceleration and question the negative sign in the result. There is also a focus on the implications of gravity on the radius of the circular motion and whether it should be considered in the problem.

Discussion Status

Participants are actively engaging with the problem, exploring the relationship between the length of the string and the radius of the circle. Some guidance is offered regarding the interpretation of the negative sign in the acceleration formula, and there is recognition of the potential oversight regarding gravitational effects.

Contextual Notes

There is a noted lack of clarity in the problem statement regarding the assumption of gravitational forces, which some participants suggest may not have been adequately addressed in the context of the homework assignment.

Rijad Hadzic
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Homework Statement


A child swings a tennis ball attached to a .750 m-string in a horizontal circle above his head at a rate of 5.00 rev/s What is the centripetal acceleration of the tennis ball?

Homework Equations


angular speed \omega = 2pi/T
speed = r\omega

a_c = -v^2 /r
a_c = -\omega ^2 r

The Attempt at a Solution


So its 5 rev/s, or .2s in 1 revolution. Using angular speed I get 10pi radians per second
Plugging in,

a_c = -(10pi)^2 (.750 m) = -740 m/s^2

But my books answer is 740 m/s^2.

I don't understand why my answer is negative, even though I used the correct formulas. Does anyone know why?
 
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Rijad Hadzic said:
I don't understand why my answer is negative
The minus sign is in the formula because the acceleration vector is in the opposite direction to the radius vector. But you are working with scalars, not vectors, so you can drop the minus sign and just say in words which way the acceleration is (if you need to specify it, which you probably do not here).
By the way, the answer is not quite right. The given distance is the length of the string, not the radius of the circle. Gravity should be taken into account.
 
haruspex said:
By the way, the answer is not quite right. The given distance is the length of the string, not the radius of the circle. Gravity should be taken into account.

What does gravity have to do with the length of the string??
 
Rijad Hadzic said:
What does gravity have to do with the length of the string??
It does not alter the length of the string, but it does alter the radius of the circle.
 
haruspex said:
It does not alter the length of the string, but it does alter the radius of the circle.

Oh I see. I got you I think I understand why. I'm not sure why but the question didn't state assume no force of gravity, but I think it was suppose to. This is in the 2d motion chapter in my first physics class, so I don't think they consider stuff like that yet.
 
Rijad Hadzic said:
Oh I see. I got you I think I understand why. I'm not sure why but the question didn't state assume no force of gravity, but I think it was suppose to. This is in the 2d motion chapter in my first physics class, so I don't think they consider stuff like that yet.
As you found, the centripetal acceleration is roughly 75g, so in this case the shortening in radius is very small and can be ignored.
 

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