Please help with the following problem: 1. A front-loading clothes washer has a horizontal drum that is thoroughly perforated with small holes. Assuming it to spin dry at 1 rotation per second, have a radius of 42 cm, and contain a 3.9 kg wet Teddy bear, what maximum force is exerted by the wall on the bear? 2. The first step I took was change 42 cm to .42m The main formula I used was Fc= mass (V^2/r) R=.42m T= 1 second Mass = 3.9 kg I figured V = 2pi(r)/t = 2 (3.14)(.42)/1 = 2.6389 Fc = 3.9 x (2.6389^2 / .42m = 64.664 According to the online hwk, this answer is incorrect. Please let me know where I am going wrong. Thanks.