Centripetal Force Calc Question

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SUMMARY

The centripetal force required to rotate a 3 kg object in a circle with a radius of 3 m at one revolution per second is calculated using the formulas Fc = MV²/r and V = 2πr/t. The velocity (V) is determined to be 18.85 m/s, leading to a centripetal force (Fc) of 355.32 N. The calculations are confirmed to be correct, providing reassurance for the individual struggling with circular motion concepts.

PREREQUISITES
  • Understanding of centripetal force (Fc) and its formula
  • Knowledge of circular motion and velocity calculations
  • Familiarity with the mathematical constant π (pi)
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation of the centripetal force formula (Fc = MV²/r)
  • Learn about angular velocity and its relationship to linear velocity
  • Explore real-world applications of centripetal force in engineering
  • Practice additional problems involving circular motion and centripetal force
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Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for examples of centripetal force calculations.

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Homework Statement



Calculate the centripetal force required to rotate a 3Kg object in a circle at a radius of 3m at one revolution per second?

Ok for some reason i find circular motion a real struggle i have come up with an answer for this question but looking for some reassurance i am on the right lines.

Homework Equations



Fc = MV2/r

V = 2\pir/t

The Attempt at a Solution



First i need to work out the velocity so i use V = 2\pir/t

V = (2\pi x 3)/1
V = 18.85 m/s1

With this i then used the Fc = MV2/r equation to work out the centripetal force as below.

Fc = (3 x 18.852)/3
Fc = 355.32 N

As i said at the beginning of this post i lack confidence in circular motion so would appreciate a pointer in the right direction if i have gone astray.
 
Physics news on Phys.org
It's just fine.
 
Quinzio said:
It's just fine.

Thanks for the reassurance.
 

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