Centripetal Force: Calculate Tension for 35kg Boy

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SUMMARY

The discussion focuses on calculating the tension in a rope for a 35kg boy swinging in a circular motion with a rope length of 7 meters and a speed of 3 m/s. The initial calculation using the formula F=(m*v^2)/R yielded 45N, which was incorrect. The correct tension is calculated by adding the gravitational force (weight) of the boy, resulting in a total tension of 388N when using the equation T = F + mg, where g is 9.8 m/s².

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  • Knowledge of centripetal force calculations
  • Familiarity with gravitational force equations
  • Basic algebra for solving equations
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Homework Statement



A 35kg boy is swinging on a rope 7 m long. He passes through the lowest position with a speed of 3 m/sec. What is the tension in the rope at that moment?

Homework Equations



F=ma
F=(m*v^2)/R
v=(2pi*r)/T

The Attempt at a Solution



F=(35*3^2)/7=45N

The correct answer is supposed to be 388 though.
 
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Remember there is also the weight of the boy
 
Oh...yeah...thanks! That does it. 45+35*9.8=388.
 

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