Centripetal force while a car makes a turn

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SUMMARY

The discussion focuses on calculating centripetal force and acceleration while a car makes a turn, specifically analyzing the forces acting on fuzzy dice hanging from a string. Key solutions identified include the tension in the string and the frictional force between the road and the car as contributors to centripetal force. The centripetal acceleration was calculated to be 4.2 m/s², leading to a radius of 171.3 meters using the formula a = v²/r. Participants emphasized the importance of accurate calculations and avoiding rounding errors.

PREREQUISITES
  • Understanding of centripetal force and acceleration concepts
  • Familiarity with free body diagrams
  • Knowledge of the formula a = v²/r
  • Basic principles of frictional forces
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  • Study the derivation and applications of centripetal force equations
  • Learn how to create and interpret free body diagrams
  • Explore the effects of friction on vehicle dynamics
  • Investigate the relationship between tangential velocity and centripetal acceleration
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This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding the dynamics of vehicles during turns.

greenrichy
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Homework Statement
A pair of fuzzy dice is hanging by a string from the rearview window. While making a right turn at 60 mph, the fuzzy dice makes an angle of 23 degrees from the vertical.
(1) Determine the radius of the circular path of the fuzzy dice.
(2) What is the mechanical force acting as the centripetal force on the following entities:
(a) - The fuzzy dice
(b) - The car
(c) - The driver
Relevant Equations
None
Correct me if I'm wrong, but I think it is not possible to solve (1) with all the data that's given.

As for (2), I have come up with the following solutions:
(a) - The tension in the string acts as the centripetal force on the fuzzy dice
(b) - The frictional force between the road and the car
(c) - None?
 
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greenrichy said:
Correct me if I'm wrong, but I think it is not possible to solve (1) with all the data that's given.

It is. Start with a free body diagram. Write some equations. Some things cancel.
 
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greenrichy said:
As for (2), I have come up with the following solutions:
(a) - The tension in the string acts as the centripetal force on the fuzzy dice
(b) - The frictional force between the road and the car
(c) - None?

(a) I would say it's the horizontal component of the string tension.
(b) Correct
(c) Are you sure? Does the driver move in a straight line?
 
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CWatters said:
It is. Start with a free body diagram. Write some equations. Some things cancel.
Thanks for your reply. From a free body diagram of FD (Fuzzy dice), I know that we can find the centripetal acceleration, right? But how do I find the tangential velocity?
 
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greenrichy said:
how do I find the tangential velocity?
How is the velocity you are given not the tangential velocity?
 
haruspex said:
How is the velocity you are given not the tangential velocity?
So the tangential velocity with which the dice swing is the same as the car's velocity?
 
greenrichy said:
So the tangential velocity with which the dice swing is the same as the car's velocity?
Depending exactly on where the dice are laterally within the car and how long the string is, the two speeds are unlikely to be exactly the same, but near enough. It is clear you are expected to take them as the same, but well spotted that they need not be.
 
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haruspex said:
Depending exactly on where the dice are laterally within the car and how long the string is, the two speeds are unlikely to be exactly the same, but near enough. It is clear you are expected to take them as the same, but well spotted that they need not be.
So I found that the centripetal acceleration is equal to 4.2 m/s^2. Given all the data that I have, the radius of the circular path of the dice turns out to be 171.3 meters. I calculated it using this formula --> a = v^2/r.

Does it look right?
 
greenrichy said:
So I found that the centripetal acceleration is equal to 4.2 m/s^2. Given all the data that I have, the radius of the circular path of the dice turns out to be 171.3 meters. I calculated it using this formula --> a = v^2/r.

Does it look right?
That’s about right. I get slightly more. Did you plug in the acceleration as exactly 4.2? That would introduce a rounding error... better to do the entire calculation in your calculator with no intermediate rounding.
Anyway, you are quoting too many sig figs given the input data.
 
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haruspex said:
That’s about right. I get slightly more. Did you plug in the acceleration as exactly 4.2? That would introduce a rounding error... better to do the entire calculation in your calculator with no intermediate rounding.
Anyway, you are quoting too many sig figs given the input data.
Got it, that makes sense. Thank you for your help.
 

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