Chain and Elastic string problem

Click For Summary
SUMMARY

The problem involves a uniform chain of length L hanging from an elastic string, which stretches by L when in equilibrium. The force constant 'k' of the string is determined by the equation k = mg/L, where 'm' is the mass of the chain. When the chain is cut at a distance 'x' from the bottom, the conservation of energy principle leads to the conclusion that x must equal (3/4)L for the upper end of the chain to just strike the ceiling. This solution is confirmed as correct based on the energy considerations discussed.

PREREQUISITES
  • Understanding of Hooke's Law and elastic potential energy
  • Knowledge of conservation of energy principles
  • Familiarity with basic mechanics involving forces and mass
  • Ability to manipulate algebraic equations and solve for variables
NEXT STEPS
  • Study Hooke's Law in detail, focusing on elastic potential energy calculations
  • Explore conservation of energy applications in mechanical systems
  • Investigate the dynamics of elastic materials and their force constants
  • Practice solving similar problems involving chains and elastic strings
USEFUL FOR

Students in physics or engineering courses, particularly those studying mechanics and elasticity, as well as educators looking for practical examples of energy conservation principles.

Vibhor
Messages
971
Reaction score
40

Homework Statement



A uniform chain of length L hangs from an elastic string of natural length L. The upper end of the string is connected with the ceiling .When the system is in equilibrium , the string stretches by an amount L .At what distance from the lower end of the chain ,the chain should be cut so that upper end of chain just strikes the ceiling?

Homework Equations





The Attempt at a Solution



'k' is the force constant of the string and m is the mass of the chain.

From equilibrium condition kL = mg → k=mg/L

Suppose the chain is cut a distance 'x' from below .

Applying COE , (1/2)kL2 = (m/L)(L-x)g(2L)

This gives x= (3/4)L .

Is it right ?

Many Thanks
 
Physics news on Phys.org
You have argued that the energy stored in the string needs to be enough to throw the remaining mass through a height 2L ... that is well reasoned, well done.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
13
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
1
Views
4K
Replies
8
Views
3K
  • · Replies 37 ·
2
Replies
37
Views
6K