- #1

Rugile

- 79

- 1

## Homework Statement

A chain is wrapped around a disk of radius R. The tension of chain is T. What is the coefficient of friction, if when the disk is spinning at angular velocity ω, the chain slips down?

See image attached.

## Homework Equations

II Newton law

[itex] a_{centripetal} = \frac{v^2}{R}[/itex]

k = F \ N

## The Attempt at a Solution

I'm not even sure where to start - I don't really understand, why does the chain slip? Is it because friction can't 'hold' it anymore? Does chain tension depend on the rotation?

Can we say that the chain slips when F(friction) < mg ?