Chain of mass M with length L (SPhO 2009)

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SUMMARY

The discussion focuses on a physics problem involving a chain of mass M and length L that is suspended vertically and falls onto a scale. The key conclusion is that the reading on the scale when a length x of the chain has fallen is not simply mx/L due to the chain's linear momentum. Instead, applying the principle of momentum (F = dp/dt) reveals a more complex relationship that must be analyzed through proper assumptions and simplifications.

PREREQUISITES
  • Understanding of classical mechanics principles, particularly momentum.
  • Familiarity with the concept of weight and its calculation (W = mg).
  • Basic knowledge of differential equations and their application in physics.
  • Ability to analyze physical systems using free-body diagrams.
NEXT STEPS
  • Study the principles of linear momentum and its implications in dynamic systems.
  • Learn about free-body diagrams and their role in solving physics problems.
  • Explore the concept of impulse and its relationship to momentum in falling objects.
  • Investigate the effects of variable mass systems in classical mechanics.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in classical mechanics, particularly in understanding dynamic systems involving falling objects and momentum analysis.

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Homework Statement



A chain of mass M and length L is suspended vertically with its lower end touching a
scale. The chain is released and falls onto the scale. What is the reading of the scale
when a length of the chain x has fallen? You may neglect the size of the individual
links. [10]

Homework Equations



-

The Attempt at a Solution



Initial W(on scale)= Mg
Final W= mx/L
 
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Classical one.
Notice that the chain has linear momentum. By applying F = dp/dt, you will see the result is not mx/L :smile:
There are several assumptions to be made in order to simplify the problem.
 

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