(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A chain consisting of two links, each of mass 0.5 kg, is lifted vertically with an acceleration of 3.0 m/s^{2}upward.

The magnitude of the downward force exerted on the top link by the bottom link is?

2. Relevant equations

F = ma

3. The attempt at a solution

1 is the top link

2 is the bottom link

F_{1,2}= The force on 1 by 2

The F_{net}on either of the two links is (0.5kg)(3m/s^{2}) = 1.5N

so

F_{net}= F_{pull}- F_{g}- F_{1,2}

F_{pull}= 1kg(3m/s^{2}) = 3N

so

1.5N = 3N - (.5kg)(9.8m/s^{2}) - F_{1,2}

F_{1,2}= 3.4 N downward

The answer is 6.4N but i dont understand why? where did i go wrong?

this is exactly what i did on a homework assignment and got it right but this is what i did on the test and i got it wrong since the answer is 6.4N not 3.4N like i got.

Thanks for any help

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# Homework Help: Chain with 2 links lifted vertically - Force

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