# Chair leg pressure problem geez

Chair leg pressure problem....geez

## Homework Statement

A 63kg person sitting on 3.5kg chair. Four legs contact the floor, each leg with circle 1.2cm in diameter. Find pressure exerted on floor by each leg of chair (weight evenly distributed).

## Homework Equations

[{(person mass) + (chair mass)} * (9.81)] / pi (radius contact circle in meters)(4 chair legs)

## The Attempt at a Solution

63kg + 3.5kg = 66.5kg total

area = 0.00011304 m^2 each leg
area total four chair legs = 0.00045216 m^2

P = F/A

{(66.5)(9.81)} / 0.00045216 = 1442774.68 N/m^2

...thus for one leg = 360693.67 N/m^2

answer of 3.6E5 and 3.61E5 incorrect.

What am I missing here?

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Fermat
Homework Helper
The pressure is the same for all four legs. You shouldn't have divided by 4.

Pressure (on each/all chair leg(s)) = (total force) / (total area) = (partial force) / (partial area)

Goofy err on my part. Actually had the answer correct the first time with 1442774.68 but posted my answer as 1.4E6....the correct way to post my answer was 1.44E6

Thank you