Pressure exerted by 1 leg of a chair.

  • Thread starter Thread starter bfusco
  • Start date Start date
  • Tags Tags
    Pressure
Click For Summary

Homework Help Overview

The discussion revolves around estimating the pressure exerted on a floor by one leg of a chair, given the total weight of the chair and the area of the chair leg in contact with the floor. The subject area includes concepts of pressure calculation and unit conversion.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the pressure by first determining the weight on one leg of the chair and converting the area from cm² to m². Some participants question the arithmetic and conversion accuracy, particularly regarding the area calculation.

Discussion Status

The discussion is ongoing, with participants providing feedback on the arithmetic and unit conversion. There is acknowledgment of potential errors in the calculations, but no consensus has been reached regarding the correctness of the final pressure value.

Contextual Notes

There is mention of a possible error in the area conversion, and the original poster expresses doubt about the calculated pressure value. The discussion also hints at the implications of sharp chair legs on flooring, suggesting a practical consideration in the problem context.

bfusco
Messages
126
Reaction score
1

Homework Statement


Estimate the pressure exerted on a floor by one pointed chair leg (64kg on all four legs) of area = 3.0×10−2 cm^2.

The Attempt at a Solution


first i found the weight of the chair (mg) to be 627.2 N, and the weight on 1 leg is 1/4th of that, so the weight on one leg is 156.8 N. then i convert .03x10^-2 cm^2 to m^2 by dividing by 10000 to get 3x10^-6. Since pressure is =F/A , i take 156.8/3x10^-6 to get 5.2x10^7 or 52,266,666 which i have a hard time believing is correct.
 
Physics news on Phys.org
Go back over your arithmetic. I think you have an error in what you have laid out here.
 
OldEngr63 said:
Go back over your arithmetic. I think you have an error in what you have laid out here.

well i did see that i typed the given area of the bottom of the chair leg wrong while i was describing what i did thus far, but aside from that the conversion from cm^2 to m^2 seems correct to me (3x10^-2 → 3x10^-6). unless my method for coverting was done incorrectly.
 
bfusco said:

Homework Statement


Estimate the pressure exerted on a floor by one pointed chair leg (64kg on all four legs) of area = 3.0×10−2 cm^2.

The Attempt at a Solution


first i found the weight of the chair (mg) to be 627.2 N, and the weight on 1 leg is 1/4th of that, so the weight on one leg is 156.8 N. then i convert .03x10^-2 cm^2 to m^2 by dividing by 10000 to get 3x10^-6. Since pressure is =F/A , i take 156.8/3x10^-6 to get 5.2x10^7 or 52,266,666 which i have a hard time believing is correct.

Your result looks okay; After all, these are rather sharp chair legs! With a cross sectional area of 3 x 10-2 cm2, if they're circular then their radius is about 1 mm. The hardwood floors would sure take a beating!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
9K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 1 ·
Replies
1
Views
7K
Replies
6
Views
5K
Replies
170
Views
8K