Change in entropy at constant temperature

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ricof
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Homework Statement



Calculate the entropy change when 0.011m3 of a perfect gas at a constant temperature of 273K is compressed from an initial pressure 1x10^5 N/m/m to a pressure of 1x10^6 N/m/m.

I know the equation but cannot work out Q! Please help!

Homework Equations



dS=Q/T

The Attempt at a Solution

 
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Some more relevant equations.
The first law
[tex]\Delta E=Q+W[/tex]
Work for isothermal expansion
[tex]W=-nRTln\frac{V_{f}}{V_{i}}[/tex]

If you combine this with what you know about change in internal energy at constant temperature, like Mapes said, and that integral of yours, you can figure out the answer.
 
Because T is constant, there is no change in internal energy right?

And also, in the above equation for isothermal expansion, how is n calculated?
 
Last edited:
ricof said:
Because T is constant, there is no change in internal energy right?

And also, in the above equation for isothermal expansion, how is n calculated?

Agreed on the first question. For the second: apply the ideal gas law.
 
Ok, so as dE = 0,

Q = -W

and as PV = nRT,

-W=PV ln (v1/v2) which is Q

Thanks guys, my answer is correct. Thanks for helping!