The discussion focuses on calculating the change in electrical potential energy (Uelec) for a Na+ ion transitioning from an electric potential of -70 mV inside a cell to 0 V outside the cell. The correct approach involves recognizing that the change in voltage is +0.07 V, calculated as 0 V - (-0.07 V). To convert this change into electronvolts (eV), one must multiply the charge of the ion (1.6 x 10-19 C) by the change in voltage, resulting in Uelec expressed in Joules, which can be converted to eV.
PREREQUISITESThis discussion is beneficial for students in physics or biology, particularly those studying cellular physiology, electrochemistry, or anyone needing to understand the principles of electrical potential energy in ions.
First off, the change in voltage is positive. To see this, use final minus initial:csimon1 said:Homework Statement
A Na+ ion moves from inside a cell, where the electric potential is -70 mV, to outside the cell, where the potential is 0 V.
Uelec = ? eV
Homework Equations
I thought you would convert -70 mV to V (therefore it would be -.07) and multiply it by 1.6*10e-19 C. But it is rejecting my answer so I don't know what formula to use.
The Attempt at a Solution
See above.