[SOLVED] change in kinetic energy in a 2-car collision 1. The problem statement, all variables and given/known data When cars are equipped with flexible bumpers, they will bounce off each other during low-speed collisions, thus causing less damage. In one such accident, a 1850kg car traveling to the right at 1.60m/s collides with a 1450kg car going to the left at 1.10m/s . Measurements show that the heavier car's speed just after the collision was 0.270m/s in its original direction. You can ignore any road friction during the collision. a) What was the speed of the lighter car just after the collision? got this to be .597m/s b) (where I'm stuck) Calculate the change in the combined kinetic energy of the two-car system during this collision. 2. Relevant equations [tex]\Delta[/tex]K = K2-K1? 3. The attempt at a solution I'm pretty sure I'm missing something obvious, but I'v tried like 5 different combinations. (1/2(ma + mb)(v2a+v2b)^2)-(1/2(ma+mb)(v1a+v1b)^2) = 190J wrong with other combos I've gotten as high as 1490J which was also wrong. any help is greatly appreciated.