Change in Potential energy equals change in Kinetic energy?

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SUMMARY

The discussion centers on the relationship between changes in potential energy (PE) and kinetic energy (KE) as described by the Work-Kinetic Energy Theorem. The equations PE = mgh and KE = 0.5mv² are established, with the key insight that W = ΔKE = -ΔPE only holds when total mechanical energy is conserved. In scenarios where external work is done, such as pushing a block up an incline at constant velocity, the net work can be zero while potential energy increases, indicating that the relationship does not universally apply. The correct formulation in such cases is ΔKE + ΔPE = Wnc, where Wnc represents work done by non-conservative forces.

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  • Understanding of the Work-Kinetic Energy Theorem
  • Familiarity with potential energy (PE = mgh) and kinetic energy (KE = 0.5mv²) equations
  • Knowledge of conservative and non-conservative forces
  • Basic principles of mechanical energy conservation
NEXT STEPS
  • Study the implications of the Work-Kinetic Energy Theorem in various mechanical systems
  • Explore the differences between conservative and non-conservative forces
  • Learn about energy conservation in isolated systems
  • Investigate real-world applications of potential and kinetic energy in physics problems
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Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of energy conservation and the dynamics of forces in motion.

EMdrive

Homework Statement


I'm trying to digest the concept of change in potential energy being set equal to a change in kinetic energy. Does this relationship always hold? Please see below for more details.

Homework Equations



PE = mgh
KE = .5mv^2
W = ΔKE = -ΔPE
W = f*d

The Attempt at a Solution


[/B]
Lets say I have a block that is being pushed up an incline at constant velocity by a force F for a distance d. Because the velocity is constant, it follows that the net force on the object is 0, and therefore the total work done on the object should also be 0. This is further explained by the W = ΔKE equation in which the final and initial kinetic energies are the same, resulting in a work of 0 J. However, what baffles me is that while kinetic energy is clearly not changing, the potential energy is (height of the object is increasing). So the relationship W = ΔKE = -ΔPE does not hold because change in potential energy is some non-zero value... Can someone explain?
 
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EMdrive said:

Homework Statement


I'm trying to digest the concept of change in potential energy being set equal to a change in kinetic energy. Does this relationship always hold? Please see below for more details.

Homework Equations



PE = mgh
KE = .5mv^2
W = ΔKE = -ΔPE
W = f*d

The Attempt at a Solution


[/B]
Lets say I have a block that is being pushed up an incline at constant velocity by a force F for a distance d. Because the velocity is constant, it follows that the net force on the object is 0, and therefore the total work done on the object should also be 0. This is further explained by the W = ΔKE equation in which the final and initial kinetic energies are the same, resulting in a work of 0 J. However, what baffles me is that while kinetic energy is clearly not changing, the potential energy is (height of the object is increasing). So the relationship W = ΔKE = -ΔPE does not hold because change in potential energy is some non-zero value... Can someone explain?

Net work done is zero .Work done by gravity is non zero . PE is negative of work done by gravity .Hence PE is non zero .

Total mechanical energy is not conserved in this case .
 
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I see, that explains it. So the equation W = ΔKE = -ΔPE only applies in situations where total mechanical energy is conserved, which is not the case here (mechanical energy should be increasing here, correct?). But, just trying to understand, work can be 0 and the total mechanical energy of the system can still increase?
 
I just noticed it is your first post .

Welcome to PF !

EMdrive said:
I see, that explains it. So the equation W = ΔKE = -ΔPE only applies in situations where total mechanical energy is conserved, which is not the case here (mechanical energy should be increasing here, correct?). But, just trying to understand, work can be 0 and the total mechanical energy of the system can still increase?

W = ΔKE is Work Kinetic Energy theorem .W is net work done on the particle .This can further be written as Wnc + Wc =ΔKE . Wnc is work done by non conservative forces ( in your example it is work done by external agent pushing the block up .Wc is work done by conservative force ( in your example it is work done by gravity ) .

Now if you write Wc as -∆PE , Work KE theorem can be rewritten as ∆KE+∆PE = Wnc . This is the complete relation .It also applies in your case .In your example ,since Wnc ≠0 , ∆KE+∆PE ≠ 0 .

In your example net work done W = 0 . ∆KE+∆PE = Work done by external agent (whosoever is pushing the block up )

∆KE+∆PE = 0 only when conservative forces are acting .Here the force exerted by agent pushing the block up is a non conservative force .

Hence correct relation to use in your example is ∆KE+∆PE = Wnc .
 
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As @conscience explained, ∆KE= -∆PE for systems in which the following is true:

(1) no external work is done on the system (e.g., system is "isoloated")

(2) internal work is done by conservative forces only (like gravity or springs).

For a modern video on this concept using fancy, mind-blowing graphics, see
 
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conscience said:
I just noticed it is your first post .

Welcome to PF !
W = ΔKE is Work Kinetic Energy theorem .W is net work done on the particle .This can further be written as Wnc + Wc =ΔKE . Wnc is work done by non conservative forces ( in your example it is work done by external agent pushing the block up .Wc is work done by conservative force ( in your example it is work done by gravity ) .

Now if you write Wc as -∆PE , Work KE theorem can be rewritten as ∆KE+∆PE = Wnc . This is the complete relation .It also applies in your case .In your example ,since Wnc ≠0 , ∆KE+∆PE ≠ 0 .

In your example net work done W = 0 . ∆KE+∆PE = Work done by external agent (whosoever is pushing the block up )

∆KE+∆PE = 0 only when conservative forces are acting .Here the force exerted by agent pushing the block up is a non conservative force .

Hence correct relation to use in your example is ∆KE+∆PE = Wnc .
Thank you so much for the concise and complete explanation. It finally makes sense now! I really appreciate the help :)
 

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