(adsbygoogle = window.adsbygoogle || []).push({}); 1b]1. Gas is confined in a tank at a pressure of

6.5 atm and a temperature of 9.4◦C.

If half of the gas is withdrawn and the

temperature is raised to 62.4◦C, what is the

new pressure in the tank? Answer in units of

atm.

2. PV=nRT

Ti= 9.4 C + 273= 282.4K

Tf= 62.4 C +273= 335.4K

3. PV= nRT, n and R are constants, therefore I used PV= T

So, initially, 6.5atmVi= 282.4K giving, Vi = 43.446

I then used (1/2) 43.446 as Vf and solved for Pf

Pf= Tf/ Vf=> 15.439 atm

But this isn't right, I know. What am I missing?? .

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# Homework Help: Change in pressure using PV=nRT

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