1b]1. Gas is confined in a tank at a pressure of 6.5 atm and a temperature of 9.4◦C. If half of the gas is withdrawn and the temperature is raised to 62.4◦C, what is the new pressure in the tank? Answer in units of atm. 2. PV=nRT Ti= 9.4 C + 273= 282.4K Tf= 62.4 C +273= 335.4K 3. PV= nRT, n and R are constants, therefore I used PV= T So, initially, 6.5atmVi= 282.4K giving, Vi = 43.446 I then used (1/2) 43.446 as Vf and solved for Pf Pf= Tf/ Vf=> 15.439 atm But this isn't right, I know. What am I missing?? .