What is d(theta-hat)/d(theta) in Cylindrical Coordinates?

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In cylindrical coordinates, the derivative d(theta-hat)/d(theta) is discussed, with initial thoughts suggesting it could be -rho or -rho*theta-hat. Clarification is provided that the correct expression is indeed -rho*theta-hat. This resolves the confusion the original poster was experiencing. The conversation emphasizes understanding the relationship between the coordinate system and the directional derivatives. Overall, the discussion highlights the importance of accurately interpreting derivatives in cylindrical coordinates.
khfrekek1992
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Homework Statement



In cylindrical coordinates: what is d(theta-hat)/d(theta)?

Homework Equations





The Attempt at a Solution



I'm fairly certain it is -rho... without a direction? or is it -rho*theta-hat?

Thanks in advance!
 
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-\hat r
 
ooh, awesome, that fixes the problem I was having.. thank you!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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