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kal8578

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- TL;DR Summary
- When a particle subjected to a conservative force has a constraint between multiple coordinates, one can change variables in the potential energy. But doing so seems to change the gradient, and thus the force, and I do not understand why.

Hello,

I am having some confusions in what should be basic pointwise Newtonian mechanics, and would like to get some help with that. It is all about changing coordinates in potential energies.

Let us start by considering a point particule in a 2d world with an axis x (left-right) and an axis z (up-down) with constant gravitational acceleration g (like on Earth). Said particle, of mass m, lies on a ground of shape z = f(x).

In what follows, I will further refine the analysis to z = αx

While the potential energy of the particle is V(x) = mg αx

T = 1/2m(\dot{x}

So that conservation of energy yields

1/2m(1+4α

Which is not of the form required for an harmonic oscillator, namely $... \dot{x}α

To get an harmonic oscillator, the choice of f(x) should be different : essentially, one should introduce s the curvilinear abscissa along the z=f(x) curve, so that T = m \dot{s}α

Why can I just not write (as the usual ``think of potential energies as landscapes on which a ball can roll'' way of thinking goes):

V(x) = α m g x

And use from there Newton's law of motion to derive, with \vec{r} the position of the mass m:

m \ddot{\vec{r}} = - \vec{\nabla} V = - 2 α m g x e

which projected on the x-axis, yields

m \ddot{x} = - 2 α m g x

which is an harmonic oscillator equation ?

In general,

- Why can't I change coordinates in potential energies?

- How to know which choices of coordinates lead to correct results?

Thanks !

PS : Sorry for the typesetting I don't know how to make LaTeX work on this website

I am having some confusions in what should be basic pointwise Newtonian mechanics, and would like to get some help with that. It is all about changing coordinates in potential energies.

Let us start by considering a point particule in a 2d world with an axis x (left-right) and an axis z (up-down) with constant gravitational acceleration g (like on Earth). Said particle, of mass m, lies on a ground of shape z = f(x).

In what follows, I will further refine the analysis to z = αx

^{2.}**What I think to be true (tell me if it's not !)**While the potential energy of the particle is V(x) = mg αx

^{2}, which is quadratic - like 1/2kx^{2}- its motion is not that of an harmonic oscillator. The reason behind that is that the kinetic energy readsT = 1/2m(\dot{x}

^{2}+\dot{z}^{2}) = 1/2m(1+4α^{2.}x^{2.})\dot{x}^{2.}So that conservation of energy yields

1/2m(1+4α

^{2.})\dot{x}^{2}+ mg α^{2}= cstWhich is not of the form required for an harmonic oscillator, namely $... \dot{x}α

^{2}+ ... xα^{2}= cst$.To get an harmonic oscillator, the choice of f(x) should be different : essentially, one should introduce s the curvilinear abscissa along the z=f(x) curve, so that T = m \dot{s}α

^{2}/2, and choose f so that f(s) is proportional s^{2}.**My problem**Why can I just not write (as the usual ``think of potential energies as landscapes on which a ball can roll'' way of thinking goes):

V(x) = α m g x

^{2}And use from there Newton's law of motion to derive, with \vec{r} the position of the mass m:

m \ddot{\vec{r}} = - \vec{\nabla} V = - 2 α m g x e

_{x}which projected on the x-axis, yields

m \ddot{x} = - 2 α m g x

which is an harmonic oscillator equation ?

In general,

- Why can't I change coordinates in potential energies?

- How to know which choices of coordinates lead to correct results?

Thanks !

PS : Sorry for the typesetting I don't know how to make LaTeX work on this website

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