Change of variables of differential equation

Click For Summary
The discussion focuses on changing variables in a differential equation involving dependent variables W, U, and Z. The user is attempting to transform the equation into a rotating frame using specific transformations for x and y. They seek guidance on how to apply the chain rule to change the differentials with respect to y into the new variables. The chain rule is outlined, indicating how to express the derivatives in terms of the new variables x' and y'. The conversation highlights the complexities of variable transformation in differential equations and the application of calculus principles.
climbon
Messages
16
Reaction score
0
I have an equation that I am trying to change the variables of, it has the form;

<br /> <br /> \frac{d}{dt} W = g \frac{\partial}{\partial y} U + h x \frac{\partial^2}{\partial y^2} Z<br /> <br />

Where W, U and Z are my dependent variables (This equation is just one of 3 coupled equations but have written only the above in general form).

I want to change the variables into a rotating frame, so;

x -----> x' = x(0) cos(wt) + y(0) sin(wt)
y -----> y' = -x(0) sin(wt) + y(0) cos(wt)

When putting these into the top equation, obviously it is simple to replace the x and y's but how do I change the differentials w.r.t. y with the new variable?

Thanks for any help :D
 
Mathematics news on Phys.org
So you have a change of variables that looks like:
x'=x'(x,y,t)
y'=y'(x,y,t)
t'=t

Chain rule:

df/dy = df/dx' * dx'/dy + df/dy'*dy'/dy + df/dt'*dt'/dy= sin(wt)df/dx' +cos(wt)df/dy'

Sorry, I'm not sure how to use latex here. d is supposed to mean a partial d.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 17 ·
Replies
17
Views
3K