- #1

terryfields

- 44

- 0

with u=x-y, v=x+y

with a transformation from f(x,y) to f(u,v) which isn't really needed for what I am about to ask

i get he jacobian as 1/2

then get y=(v-u)/2 and x=(u+v)/2 all of which i know is right as i have the answers, this is purely revision

then when changing the limits i get every step until the last one which are

0<x<pi/2

0<(u+v)/2<pi/2

0<u+v<pi

-u<v<pi-u

**0<u<pi**<<<<<<<<<<<where does that come from