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Changing Potential Energy of a Magnetic Coil

  1. Jun 15, 2008 #1
    1. The problem statement, all variables and given/known data

    A coil with magnetic moment 1.40 Am^2 is oriented initially with its magnetic moment antiparallel to a uniform magnetic field of magnitude 0.830 T.

    What is the change in potential energy of the coil when it is rotated 180 degrees, so that its magnetic moment is parallel to the field?

    2. Relevant equations

    u = IA = magnetic moment

    U = -uBcos(phi)

    3. The attempt at a solution

    U1 = -uBcos(180) = -1.162J
    U2 = -uBcos(360) = 1.162J

    deltaU = U2-U1 = 1.162J - (-1.162J) = 2.324J

    just wondering if I did the problem correctly, I'm not sure I have the correct angles; any help is greatly appreciated.
     
  2. jcsd
  3. Jun 15, 2008 #2
    It's just [tex]\Delta U = \mu B[/tex] since [tex]U=-\mu B cos(\phi)=-\mu B cos(180) =-\mu B*(-1)=\mu B[/tex]
     
  4. Jun 15, 2008 #3
    I actually tried that before and it came out incorrect.

    edit: which is strange since reviewing my concepts again showed that the antiparallel (perpendicular) potential energy should have been 0 so more than likely it should have turned out like you said.

    would it be possible that the trig function as changed?
     
    Last edited: Jun 15, 2008
  5. Jun 15, 2008 #4
    it turns out I was correct (according to masteringphysics in this case the first antiparallel angle was 180 degrees) but the sign was negative, turns out it was like this:

    U = Uf-Ui

    = (-1.4*.830*cos(360))-(-1.4*.830*cos(180)) = -2.324J

    thanks for the help anyway dude.
     
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