Changing variable in a sumation

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The discussion revolves around the manipulation of a summation by changing the variable from k to m, specifically in the expression \sum_{k=n+1}^{0} -k 3^k. The transformation involves substituting m = -k, leading to the new summation \sum_{m=0}^{-n-1} m (\frac{1}{3})^m. The limits of the summation change accordingly, with k=n+1 becoming m=-n-1 and k=0 becoming m=0. The reasoning behind the change in limits is clarified, confirming that altering the sign necessitates adjusting the values in the summation. This manipulation demonstrates the flexibility of summation notation when changing variables.
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Homework Statement


I have been shown this manipulation of a summation and I am wondering why the person could do it:
\sum_{k=n+1}^{0} -k 3^k

Now change the variables with m=-k and we get:

\sum_{m=0}^{-n-1} m (\frac{1}{3})^m

The Attempt at a Solution



I can see where the m (\frac{1}{3})^m came from (just stick -m in for the k), but how did the summation change?
 
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Well, k=n+1 corresponds to m=-k=-n-1, and k=0 corresponds to m=0, so the new limits are m=0, m=-n-1.
 
That much is obvious, but why is the 0 on the bottom and the -n-1 on the top now?
 
Never mind, that question is obvious also. Of course if you change the sign you would have to move the values on the summation... Problem solved.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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