Characteristic and minimal polynomials

  • Thread starter corey2014
  • Start date
  • #1
22
0

Homework Statement


Let V be a finite dimensional complex vector space and T be the linear operator of V. Prove that the following are equivalent

a V has a basis consisting of eigenvectors of T.
b T can be represented by a diagonal matrix.
c all the eigenvalues of T have multiplicity one.
d. the Characteristic polynomial of T equals the minimal polynomial of T.


Homework Equations



Not really applicable

The Attempt at a Solution



Ok so I proved A implies B, However, I feel that B does not imply C.

I just want to see if my argument is valid. because the identity matrix, is definitely diaganol however, it does not have a multiplicity of One. Can I assume wlog that T has distinct eigenvalues along the main diaganol?
 

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
26,260
619
You are quite right. But I wouldn't assume wlog. That looses generality. B doesn't imply C period. I think whoever wrote the problem up had a memory lapse or forgot to state an assumption. You could assume they forgot that assumption and proceed from there.
 
Last edited:
  • #3
HallsofIvy
Science Advisor
Homework Helper
41,833
961

Homework Statement


Let V be a finite dimensional complex vector space and T be the linear operator of V. Prove that the following are equivalent

a V has a basis consisting of eigenvectors of T.
b T can be represented by a diagonal matrix.
c all the eigenvalues of T have multiplicity one.
??? There are two "multiplicities", the geometric multiplicity (number of independent eigenvectors corresponding to the eigenvalue) and algebraic multiplicity (multiplicity as a root of the characteristic polynomial). But neither of those must be one in order that T can be represented by a diagonal matrix, only that, for each eigenvalue, the two multiplicities be the same.

d. the Characteristic polynomial of T equals the minimal polynomial of T.


Homework Equations



Not really applicable

The Attempt at a Solution



Ok so I proved A implies B, However, I feel that B does not imply C.

I just want to see if my argument is valid. because the identity matrix, is definitely diaganol however, it does not have a multiplicity of One. Can I assume wlog that T has distinct eigenvalues along the main diaganol?
 

Related Threads on Characteristic and minimal polynomials

  • Last Post
Replies
3
Views
2K
Replies
0
Views
883
Replies
3
Views
3K
Replies
2
Views
4K
Replies
6
Views
5K
Replies
1
Views
2K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
11
Views
3K
Replies
4
Views
3K
Replies
1
Views
2K
Top