Is Charge Density Zero for a Uniform E-field in y-direction?

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SUMMARY

The discussion centers on the evaluation of charge density in a uniform electric field described by the function E(x,y,z,t) = E_o cos(k(x-ct)) ∈ j. The key conclusion is that the divergence of the electric field, calculated using the equation ∇·E = ρ/ε_o, results in zero due to the absence of variation in the y-direction. Consequently, the charge density (ρ) in this region of space is confirmed to be zero.

PREREQUISITES
  • Understanding of vector calculus, specifically divergence.
  • Familiarity with electric field concepts and Maxwell's equations.
  • Knowledge of charge density and its relation to electric fields.
  • Basic proficiency in using mathematical functions and trigonometry.
NEXT STEPS
  • Study vector calculus, focusing on divergence and its physical implications.
  • Explore Maxwell's equations, particularly the relationship between electric fields and charge density.
  • Investigate uniform electric fields and their characteristics in electrostatics.
  • Learn about the implications of charge density in various physical contexts, such as capacitors.
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and anyone studying electromagnetism, particularly those interested in the relationship between electric fields and charge density.

AdkinsJr
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Homework Statement


I have a function for an E-field E(x,y,z,t)=E_o\cos(k(x-ct))\hat j and I need to find the charge density...

Homework Equations



\vec \nabla \cdot\vec E=\frac{\rho}{\epsilon_o}


The Attempt at a Solution




When I compute the dot product of gradient operator with the E-field I get zero since the only "term" in the factor is in the y direction, but it also does not have any variation with y so is the charge density in this region of space just zero?
 
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AdkinsJr said:

Homework Statement


I have a function for an E-field E(x,y,z,t)=E_o\cos(k(x-ct))\hat j and I need to find the charge density...

Homework Equations



\vec \nabla \cdot\vec E=\frac{\rho}{\epsilon_o}


The Attempt at a Solution




When I compute the dot product of gradient operator with the E-field I get zero since the only "term" in the factor is in the y direction, but it also does not have any variation with y so is the charge density in this region of space just zero?

I would agree with that.
 

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