Charge moves through a circuit element and loses energy

  • Thread starter Westin
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  • #1
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Homework Statement



If +6 (C) charge moves through a circuit element, and in so doing the charge loses 12 (J) of energy, then what is the magnitude of the voltage across this circuit element?

A)2(V)
B)6(V)
C)12(V)
D)72(V)

For the same circuit element and situation described in question 1, is the +6 (C) of charge passing through a voltage rise, or a voltage drop?

A) voltage rise
B) voltage drop
C) none of the above

2. Homework Equations

V = J/C[/B]


The Attempt at a Solution



V = 12(J)/2(C) = 2(V)

Since the circuit lost energy, it will be a voltage drop because the element absorbed power.
[/B]
Is my reasoning right here? It seems too easy for it to be so simple.

Thanks
 
Last edited:

Answers and Replies

  • #2
569
85
V = 12(J)/2(C) = 2(V)
Typo [6(C)?]. Otherwise, looks OK. You can check with a basis of 1 sec then using J, V, A, and W equations.
 

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