Charge on Ion After 10V Potential Difference: Calculate?

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SUMMARY

The discussion centers on calculating the charge of an ion accelerated through a potential difference of 10V, resulting in an increase in kinetic energy of 7 J. The relevant equation used is U=qV, where U represents the change in potential energy, q is the charge, and V is the potential difference. It is established that if the kinetic energy increases while moving to a +10V higher voltage, the ion must possess a negative charge. The confusion regarding the sign of the charge is clarified, emphasizing that the magnitude of the charge is the primary concern in this context.

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  • Understanding of electric potential and kinetic energy relationships
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Homework Statement


An ion accelerated through a potential difference of 10V experiences an increase in kinetic energy of 7 J. Calculate the charge on the ion.

Homework Equations


U=qV
-qV=W

The Attempt at a Solution


My book says the charge is positive, but I think that the charge is suppose to be negative. Did the book make a mistake or am I missing something? Whether the charge is positive or negative does matter right?

Thanks for any help.
 
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If the values for the potential difference and kinetic energy seem irregular, it was because I made them up, realizing that they were not relevant to my question.
any help would be much appreciated.
 
It's sounds like they are not specifying whether the ion goes through an increase or a drop in voltage, just that the voltage changes by 10V. As such, they are probably just concerned with the magnitude of the charge, and not whether it is positive or negative.

You are correct that, if the kinetic energy increases when moving to a +10V higher voltage, then it must have a negative charge.
 

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