Charge on the capacitor after changing the switch position

  • #1
319
13

Homework Statement


73_FFCE1_F-7820-4_D4_A-_BE3_F-_CAB58_E0_EED31.jpg


Homework Equations


V = I R
Q= CV

The Attempt at a Solution


When the switch is connected to position a :
20-106 * I = 0 ( KVL)
Vc = 0 , because the switch is connected for a long time.
I = 2*10-5 A
When the switch is connected to position b :
Q/(4*10-6) - 106 *2*10-5 = 0 (KVL)
Q =8*10-5 = 80μC
Is my answer correct ?
 

Attachments

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Answers and Replies

  • #2
cnh1995
Homework Helper
Gold Member
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Vc = 0 , because the switch is connected for a long time.
Are you sure?
Is my answer correct ?
No, t=2s doesn't appear anywhere in your equations.
 
  • #3
319
13
Are you sure?

No, t=2s doesn't appear anywhere in your equations.
4%7D%20%3D%2048.png
 

Attachments

  • 4%7D%20%3D%2048.png
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