- #1
Vanessa Avila
- 94
- 1
Homework Statement
A capacitor with a capacitance of C = 5.95×10−5 F is charged by connecting it to a 12.0 −V battery. The capacitor is then disconnected from the battery and connected across an inductor with an inductance of L = 1.50 H .
What is the charge on the capacitor after a time interval of 2.30×10−2 s after the connection to the inductor is made?
Homework Equations
q(t)=Qcos(ωt+∅)
The Attempt at a Solution
I have answered a couple questions prior to this question.
I found these:
ω = 106 rad/s
Period of the electrical oscillations
T = 5.94*10^-2 s
Initial charge of the cap
Q = 7.14*10^-4 C
Energy initially stored in the cap
4.28*10^-3 J
For the question where i had to find the charge, I used
q(t)=Qcos(ωt+∅)
and got 7.13*10^-4 which is wrong. I plugged 2.30*10^-2 for time t and the ∅=0.