Charge, Potential, Work, and Electricity

  • #1
Phoenixtears
83
0
SOLVED



Homework Statement



Moving a charge from point A, where the potential is 275 V, to point B, where the potential is 150 V, takes 4.0 10-4 J of work. What is the value of the charge?


Homework Equations



V= w/q

V= change in voltage
w= work
q= charge

The Attempt at a Solution



This problem seems simple enough, but for some reason I can't get the right answer. W= 4E-4 and then I divided it by the change in V (275- 150).

4E-4/ 115= 3.478E-6

Then I mulitplied by 1E6 to change the units into micro-Coulombs.

Yet this answer is wrong. What am I doing incorrectly??

Thanks in advance for the help!

~Phoenix
 
Last edited:

Answers and Replies

  • #2
lanedance
Homework Helper
3,304
2
first 150-275 = 125 not 115

i thin you may have to be careful with signs here as well

hint dV = V2-V1, if it takes work to move a charge to a smaller potential can we say something about the charge?

Think which way the electric field is pointing and how a positive charge would want to move between the points
 
  • #3
Phoenixtears
83
0
Oh.... I see what you're saying. (Sorry about the 115 thing, that was just my typing... the actual calculation was correct).

So instead it would be 4E-4/(150-275)= -3.2 Micro-C. Thanks so much! That makes perfect sense.
 

Suggested for: Charge, Potential, Work, and Electricity

Replies
1
Views
147
Replies
4
Views
321
Replies
3
Views
290
Replies
4
Views
237
Replies
12
Views
536
Replies
3
Views
251
Replies
14
Views
672
Replies
11
Views
498
Replies
9
Views
602
Replies
6
Views
270
Top