Charged capacitors in series and both ends of wire connected

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SUMMARY

When two capacitors, specifically a 3 microfarad and a 6 microfarad capacitor, are connected in series with a voltage of 10V, the charge on each capacitor is equal due to the series configuration. After disconnecting the battery and connecting the loose ends of the wire, the potential difference across the capacitors becomes zero, effectively creating a short circuit condition. The charge stored in each capacitor remains constant, but the potential difference across the terminals is eliminated.

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jc345
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Two Capacitors are connected in series (3 microfarad and 6 microfarad) with Vab=10V. Battery is disconnected and the loose ends of wire are connected. What happens to the potential difference?Would it be zero..charge? I can't figure it out...sounds like a short circuit?
 
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(i) First, determine the charge the battery puts on each capacitor. The charge added to one capacitor = the charge added to the other, since they are in series.

(ii) ...
 

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