Charged mass connected to spring, swung in circle in mag. field

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Homework Help Overview

The problem involves a spring attached to a charged mass that is swung in a horizontal circle within a magnetic field. The mass, charge, spring constant, and magnetic field strength are provided, and the question seeks to determine the maximum radius of the mass's motion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the elongation of the spring and the radius of the circular path. There are attempts to equate forces acting on the mass, including magnetic and spring forces, but uncertainty remains about the correct application of these principles.

Discussion Status

Some participants are exploring the assumptions made regarding the elongation of the spring and its relation to the radius. There is an ongoing inquiry into the correctness of the force balance equation used in the attempts, with suggestions for reconsidering the approach.

Contextual Notes

Participants are working under the constraints of a zero-gravity environment and are questioning the definitions and relationships between the forces involved, particularly in the context of circular motion and spring dynamics.

clubguppy
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Homework Statement


A spring with an unstretched length of 20 cm and a force constant of 100 N/m is attached to a 2-kg mass with a charge of 3.0 C. The mass is swung in a circle in a zero gravity environment, so that the spring is perfectly horizontal and is parallel to the radius of the circle, as shown at right. A vertical 1.5-T magnetic field permeates the entire region.


If the mass is moving at 5 m/s, what is the maximum radius of its motion?

Homework Equations


Centripetal Force: F= \frac{mv^{2}}{r}
Hooke's Law: F=kx where k is the spring constant and x is elongation (how long the string is stretched)
Magnetic Force: F = qvBsin \theta

The Attempt at a Solution


I tried qvBsin(90 degrees) = qvB =F= \frac{mv^{2}}{r} + kr
I assumed the force on the spring itself is the tenion (the constant * how long it stretched)

I'm not sure if I did it correctly...please help.
 
Last edited by a moderator:
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What is x in F = kx ?
 
Reply

clubguppy said:

Homework Statement


A spring with an unstretched length of 20 cm and a force constant of 100 N/m is attached to a 2-kg mass with a charge of 3.0 C. The mass is swung in a circle in a zero gravity environment, so that the spring is perfectly horizontal and is parallel to the radius of the circle, as shown at right. A vertical 1.5-T magnetic field permeates the entire region.


If the mass is moving at 5 m/s, what is the maximum radius of its motion?

Homework Equations


Centripetal Force: F= \frac{mv^{2}}{r}
Hooke's Law: F=kx where k is the spring constant and x is elongation (how long the string is stretched)
Magnetic Force: F = qvBsin \theta

The Attempt at a Solution


I tried qvBsin(90 degrees) = qvB =F= \frac{mv^{2}}{r} + kr
I assumed the force on the spring itself is the tenion (the constant * how long it stretched)

I'm not sure if I did it correctly...please help.

I have updated the information in the question.
 
Last edited by a moderator:
is the elongation is equal to radius of the circular path?
 
response

mukundpa said:
is the elongation is equal to radius of the circular path?

Yes, that is what I assumed. But, I can't get the radius in real number. What did I do wrong? Do you have suggestions for what I should do?

Should I change something about qvB =F= \frac{mv^{2}}{r} + kr or do something different?
 
Last edited:

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