A positively charged particle initially at rest on the ground accelerates upward to 200m/s in 2.60s. The particle has a charge-to-mass ratio of 0.100 C/kg and the electric field in this region is constant and uniform.
What are the magnitude and direction of the electric field?
a=delta v/ delta t
Electric Fields E=F/q
Coulomb's Law F=kq/r^2 Not sure I need this one.
The Attempt at a Solution
E=(10 kg/C)(200/2.6 m/s^2) = 769.23 N/C = 7.7*10^2 N/C Direction upward.
Question seems pretty straightforward but it's telling me this answer is incorrect. If I have to incorporate Coulomb's law, I'm not sure how.