Charged particles in magnetic field

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The discussion focuses on calculating the charge-to-mass ratio (q/m) of a newly discovered particle that moves undeflected through crossed electric and magnetic fields. The electric field strength is 316 V/m, and the magnetic field strength is 0.00127 T, with the particle moving in a circular path of radius 2.97 cm when only the magnetic field is present. The velocity of the particles is calculated using the formula v=E/B, resulting in approximately 248,818.9 m/s. By applying the formula m/q=(rB')/v and simplifying, the value of q/m is determined to be approximately 0.01119723 C/kg. The discussion emphasizes the importance of unit consistency and careful substitution in calculations.
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I've been trying to work this, but the way I'm substituting, I get no variables left...:-\ It's...freaky lol.
The question is
Suppose a new particle is discovered, and it is found that a beam of these particles passes undeflected through "crossed" electric and magnetic fields, where E=316 V/m and B=0.00127 T. If the eleectric field is turned off, the particles moe in the magnetic field in circular paths of radius r=2.97 cm. Determine q/m for the particles from these data. Answer in units of C/kg.

The way I worked this is I used the foruma v=E/B to find the velocity which vame out to be 248818.8976 m/s then I plugged the v into the equation m/q=(rB')/v and since we don't know v or q those remain as variables. Then I plug the values into Em = rB'Bq and so of course, no variables left.

*sighs* help anyone?
 
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Neverrrrminnddddd lol

I used the v value that I got, and plugged it into r=(mv)/(qB)

:-D thanks ya'll
do help with my other post? lol
 


It seems like you are on the right track with your approach. Let's break down the steps and see if we can find where the issue might be.

First, we are given the electric field strength (E) and magnetic field strength (B) as well as the radius (r) at which the particles move in a circular path when only the magnetic field is present.

Using the formula v=E/B, we can find the velocity of the particles to be 248818.8976 m/s.

Next, we can use the formula m/q=(rB')/v, where B' is the magnetic field strength in the absence of the electric field. Since the particles are moving in a circular path, we can use the formula B'=Bqv/m to find B'.

Substituting B'=Bqv/m into the previous equation, we get m/q=(rBqv)/v. We can simplify this to m/q=rBq.

Now, we can use the given information of the radius (r) and the magnetic field strength (B) to find Bq. Substituting these values, we get Bq=0.00127*2.97=0.0037659.

Finally, we can substitute this value into the equation m/q=rBq to get m/q=2.97*0.0037659=0.01119723.

So, the value of m/q for the particles is 0.01119723 C/kg.

I hope this helps and clarifies the steps for solving this problem. Remember to always check your units and make sure they cancel out correctly. Good luck!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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